[Techtalk] Bash builtin "read" isn't working like I expect
Elizabeth Barham
lizzy at soggytrousers.net
Thu Oct 30 10:55:01 EST 2003
Hi Megan,
This appears to be a variable evaluation error with the '-' being
seen as a variable name delimiter:
other-file=second-file.txt
echo $other-file
results in:
./b.sh: line 6: other-file=second-file.txt: command not found
-file
The key being the second line in which $other was evaluated to "" and
"-file" passed on through by echo. This works:
other_file=second-file.txt
echo $other_file
as does:
other_file=second-file.txt
first_file=first-file.txt
while read LINE; do echo $LINE; grep $LINE $other_file; done < $first_file
Elizabeth
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