[Techtalk] cut command, print just last field

[Sabina Serbu]

Hi,

I'm trying to get the local directory (without the absolute path) on my
shell.

For the moment, I am using awk:

  pwd | awk -F'/' '{print $NF}'

Which works just fine. However, I was just wondering, do you know any
way to do this using the 'cut' command? 

I could not use something like
  pwd | cut -d'/' -f5
because this would display the last field only if there are 5 fields.
Unless there was a way for 'cut' to know the number of fields, as NF in
awk..?

Thanks!
Sabina







-- 
Sabina Serbu
 Institut d'informatique
 Université de Neuchâtel
 +41 32 718 2724
 http://members.unine.ch/sabina.serbu