[Techtalk] Joining commands together in bash

[Meredydd]

This is how I would do it:

for FILE in * ; do
  if [ x`file $FILE | grep 'shell script text executable'` != x ]; then
   head -n 3 $FILE
  fi
done

In pseudocode:

Walk through "*" (all files in current directory, obviously). For each item, 
put said item into the variable FILE, and execute the following:
	If the output of the command "file $FILE | grep 'shell script executable'" is
	not empty (ie it's a shell script), execute the following:
		head -n 3 $FILE

Meredydd

On Sunday 11 May 2003 12:20, Berenice wrote:
> I'm making a script that will display the filenames of any
> shellscripts in a directory and display the first few lines of each
> script below each filename.  So far I've come up with 2 commands for
> this script:
>
> head -n 3 *
>      Displays first 3 lines of any file in current directory
> file * | grep 'shell script text executable'
>      Displays filenames of shell scripts
>
> The problem is that I can't find a way to join them together to make
> them work.  If I do:
> file * | grep 'shell script text executable' | head -n 3 *
> I get filenames of shell scripts AND the first 3 lines of any file in
> current directory.  Head doesn't display the first 3 lines of
> shellscripts.  Can anyone suggest another way to join them together?
>
> Thanks
> Berenice
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> Berenice
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