[Techtalk] Bash functions with user-defined parameters

[Sue Stones]

I haven't done any bash shell scripting, but my guess would be to make another 
variable so that you end up with:-

 #!/bin/bash
 myfunction()
 {
 $num1 = $1
 while [ $num1 -le $2 ]
 do
  echo $num1
  #problem here...$(( $num1 + 1 ))
 done
 }


On Mon, 28 Apr 2003 10:52 pm, Berenice wrote:
> I've been messing around with bash and want to create a function that
> takes two different integers and increments the first integer by 1,
> until the first integer is the same as the second integer.  Eg: if
> there are 2 numbers, 1 and 4, add 1 to the first number until it
> becomes 4.
>
> Now I can do this interactively like this:
>
> #!/bin/bash
> echo "Enter 2 numbers:"
> read num1 num2
> while [ $num1 -le  $num2 ]
> do
>   echo $num1
>   num1=$(( $num 1 + 1 ))
> done
>
> But I'm having trouble making it into a function that executes by
> typing the function name with parameters, eg: myfunction 1 4. Here's
> what I've done so far:
>
>
> #!/bin/bash
> myfunction()
> {
> while [ $1 -le $2 ]
> do
>  echo $1
>  #problem here...$(( $1 + 1 ))
> done
> }
>
>
> The problem is with the $(( $1 + 1 )) because you can't do $1=$(( $1
> + 1 )).  Is there a way to fix this, or should I forget about using
> $1 and $2?
>
> Thanks
> Berenice
>
>
>
>
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