[prog] php help
Rachel McConnell
rachel at xtreme.com
Tue Sep 16 10:19:52 EST 2003
My PHP knowledge is minimal, but I do see a possible problem in the code
as you've sent it. Basically, you've defined a variable $query but have
not used it as you've clearly intended.
See below...
> -----Original Message-----
> equals their student number. The table I am trying to get the
> information from is called term, the rows
> I need are called term and year. I'm trying to follow examples from a
> .<?
> include "connect.inc";
>
> myconnect();
>
> $scode = 193721070;
The variable $query (which is perfectly good SQL) doesn't seem to be
used
> $query = "SELECT term, year FROM term WHERE s_code = ".$scode;
>
>
> // get current term and year
This line, you are attempting to select from a table called 'current'
which is not a table you've mentioned as existing
> $current=mysql_db_query($db,"select term, year from current");
You probably want this instead:
$current=mysql_db_query($db,$query);
> $cur=mysql_fetch_array($current);
> $cyear=$cur['year'];
> $cterm=$cur['term'];
>
> $array = mysql_fetch_array($result);
> echo $array['term']. ;
> echo $array['year']."\n";
>
> ?>.
As for the array stuff, I can't really help alas!
rachel
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