[Courses] Re : C Programming for Absolute Beginners, text book?

[Chao Yang]

----- Original Message -----
> > I subscribe to the many thanks Carla received. Best first lesson
> > ever!
> > Thanks everybody for all the comments (haven't been able to fully
> > understand all of them...) and questions which helped me think more
> > about
> > the little things.
> > 
> > My question is related to what I have encounter so far trying to
> > compile
> > other people codes: which/where is the difference in using gcc or
> > cc while
> > compiling?  I can see this example works for both of them, but I
> > know this
> > is not "universal".
> > 
> > Thanks!
> > Diana
> 
> I love when the brainiacs chime in :)
> 
> cc is linked to gcc, which you can see a number of different ways:
> 
> $ stat /usr/bin/cc
>   File: `/usr/bin/cc' -> `/etc/alternatives/cc'
>   Size: 20        	Blocks: 0          IO Block: 4096   symbolic link
> Device: 802h/2050d	Inode: 1070655     Links: 1
> Access: (0777/lrwxrwxrwx)  Uid: (    0/    root)   Gid: (    0/
>    root)
> 
> 
> $ stat /usr/bin/gcc
>   File: `/usr/bin/gcc' -> `gcc-4.6'
>   Size: 7         	Blocks: 0          IO Block: 4096   symbolic link
> Device: 802h/2050d	Inode: 1047149     Links: 1
> Access: (0777/lrwxrwxrwx)  Uid: (    0/    root)   Gid: (    0/
>    root)
> 
> 
> When you look in /etc/alternatives you see another cc > gcc links,
> and how C89
> and C99 standards support are handled:
> 
> $ ls -l /etc/alternatives | grep cc
> lrwxrwxrwx 1 root root  12 Jun  2  2011 cc -> /usr/bin/gcc
> lrwxrwxrwx 1 root root  16 Jun  2  2011 c89 -> /usr/bin/c89-gcc
> lrwxrwxrwx 1 root root  16 Jun  2  2011 c99 -> /usr/bin/c99-gcc
> 
> 
I do not have these files in my system, using of gcc v4.6 and fedora16. 
$ ll /etc/alternatives/ | grep cc
$ gcc --version
gcc (GCC) 4.6.2 20111027 (Red Hat 4.6.2-1)
Copyright (C) 2011 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.

Is that means my gcc does not have the compatibility with c89 and c99? 

> This Stackoverflow discussion goes into some interesting minutiae on
> the finer
> points of cc vs. gcc:
> 
> Invoking GCC as “cc” versus “gcc”
> http://stackoverflow.com/questions/939989/invoking-gcc-as-cc-versus-gcc
> 
> best,
> Carla
> 
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> Carla Schroder, ace Linux guru and howto author
> 541-932-4817 PT
> carla at tuxcomputing.com
> ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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Best,
Chao